对数相关知识 June 14, 2022 换底公式 logab=logcblogca=logcb⋅logac \log_a b = \frac{\log_c b}{\log_c a} = \log_c b \cdot \log_a c logab=logcalogcb=logcb⋅logac 相关结论 $$ \because a^{\log_b n} = a^{\log_a n \log_b a} \ \therefore a^{\log_b n} = n^{\log_b a} $$